I need to write the equation for the neutralization reaction of NaOH and nicotinic acid (C5H4NCOOH). Here is my attempt:
C5H4NCOOH + NaOH → C5H4NCOONa + H2O
First of all, is the formula for nicotinic acid correct? I am finding mixed answers when I search it on the internet.
Secondly, have I written the reaction correctly?
Please help!
yes and yes.
The formula you provided for nicotinic acid, C5H4NCOOH, is correct. Nicotinic acid is also known as niacin or vitamin B3.
Now let's discuss the neutralization reaction. A neutralization reaction occurs when an acid reacts with a base to form a salt and water. In this case, you have sodium hydroxide (NaOH) as the base and nicotinic acid as the acid. The reaction between them will form the salt sodium nicotinate (C5H4NCOONa) and water (H2O).
Your attempt at writing the equation is correct:
C5H4NCOOH + NaOH → C5H4NCOONa + H2O
Well done! You have correctly balanced the equation. It is important to note that in a balanced equation, the number of atoms of each element is the same on both sides of the equation.
If you would like to verify the equation or for future reference, you can follow these steps to balance the equation:
1. Start by counting the number of atoms for each element on both sides of the equation.
2. Begin balancing with the elements that appear in the fewest compounds. In this equation, we have a single carbon (C), hydrogen (H), and nitrogen (N) atom on each side.
3. Balance the carbon atoms by adjusting the coefficient in front of the sodium nicotinate (C5H4NCOONa) on the product side.
4. Balance the hydrogen and nitrogen atoms by adjusting the coefficient in front of the water (H2O) on the product side.
5. Be sure to double-check that all elements are balanced.
In this case, the equation is already balanced:
C5H4NCOOH + NaOH → C5H4NCOONa + H2O
Great job on your attempt! If you have any further questions, feel free to ask.