Homework Help: chemistry

Posted by Blair on Saturday, January 12, 2013 at 5:14pm.

A photon interacts with a ground state electron in a hydrogen atom and is absorbed. The electron is ejected from the atom and exhibits a de Broglie wavelength of 5.908×10−10 m. Determine the frequency (in hz) of the interacting photon.

chemistry - Chemgam, Saturday, January 12, 2013 at 6:46pm
E = P^2/2Me + E(first ionization)

P= h / BroglieWavelength

E(first ionization)=21.7*10^-19

Me= 9.1*10^-31

h= 6.626*10^-34

frecuency(hz)= E / h
chemistry - Anonymous, Sunday, January 13, 2013 at 3:39am
Chemgam, can you please clarify what is (P^2)? do you mean (Momentum) X (Momentum)

I made it like this, but it gave me wrong answer
chemistry - Anonymous, Sunday, January 13, 2013 at 2:19pm
P = h/ BroglieWavelength

Like he says. It is correct

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