Posted by Blair on .
A photon interacts with a ground state electron in a hydrogen atom and is absorbed. The electron is ejected from the atom and exhibits a de Broglie wavelength of 5.908×10−10 m. Determine the frequency (in hz) of the interacting photon.
E = P^2/2Me + E(first ionization)
P= h / BroglieWavelength
frecuency(hz)= E / h
Chemgam, can you please clarify what is (P^2)? do you mean (Momentum) X (Momentum)
I made it like this, but it gave me wrong answer
P = h/ BroglieWavelength
Like he says. It is correct