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March 24, 2017

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A photon interacts with a ground state electron in a hydrogen atom and is absorbed. The electron is ejected from the atom and exhibits a de Broglie wavelength of 4.548 x 10^-10m. Determine the frequency (in hz) of the interacting photon.

i got 1.45691908531e-24 but it is wrong :(

  • chemistryy - ,

    9.14E18

  • chemistryy - ,

    9.14E18 is wrong

    can you please explain how you got this number

  • chemistryy - ,

    E = P^2/2Me + E(first ionization)

    P= h / BroglieWavelength

    E(first ionization)=21.7*10^-19

    Me= 9.1*10^-31

    h= 6.626*10^-34

    frecuency(hz)= E / h

  • chemistryy - ,

    Yup, it was meant to be wrong.

    I don't like cheats.

  • chemistryy - ,

    when you gave the people wrong answer and you know that it is wrong, this is the pure cheating, stupid..!!

  • chemistryy - ,

    5.043661*10^15

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