posted by p on .
A photon interacts with a ground state electron in a hydrogen atom and is absorbed. The electron is ejected from the atom and exhibits a de Broglie wavelength of 4.548 x 10^-10m. Determine the frequency (in hz) of the interacting photon.
i got 1.45691908531e-24 but it is wrong :(
9.14E18 is wrong
can you please explain how you got this number
E = P^2/2Me + E(first ionization)
P= h / BroglieWavelength
frecuency(hz)= E / h
Yup, it was meant to be wrong.
I don't like cheats.
when you gave the people wrong answer and you know that it is wrong, this is the pure cheating, stupid..!!