Posted by selly on Saturday, January 12, 2013 at 7:35am.
Yes! I foun the correct answer. It's 7.157e15
can you please help to explain the formula
I have tried everything but don't know how the formulas go if you could please give a formula i would be very thankful
Selly could you please give the formula
First you find the Momentum (P) from the de Broglie eqn: P = h/lambda, where h is the Plancks constant.
Then you find the velocity (v) from the eqn: P = m*v, where m is the Electron Mass. Then substitute v in the KE eqn: KE = 0.5*m*v^2.
Add this KE to the Ionization Energy of H from the periodic table to find the Photon Energy.
Then Photon Energy = h*nu, where nu is the desired frequency ..
P.S: Don't forget to convert the Ionization Energy from eV to J.
First find: E = P^2/2Me + E(first ionization)
P= h / BroglieWavelength
E(first ionization)=21.7*10^-19
Me= 9.1*10^-31
h= 6.626*10^-34
Once E is found the find frequency:
frequency(hz)= E / h
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