posted by Ankur on .
A photon interacts with a ground state electron in a hydrogen atom and is absorbed. The electron is ejected from the atom and exhibits a de Broglie wavelength of 0.468×10−10 m. Determine the frequency (in hz) of the interacting photon.
frequency*wavelength=speed of light
not correct answer - this is a de Broglie wave ;)
First find: E = P^2/2Me + E(first ionization)
P= h / BroglieWavelength
Once E is found the find frequency:
frequency(hz)= E / h
It is wrong rex.