Homework Help: Chemistry

Posted by T on Friday, January 11, 2013 at 6:56pm.

The solubility of bismuth iodide (BiI3) in water is 10.291 x 10-3 M. Calculate the value of the solubility product. The dissolution products are Bi3+(aq) and I−(aq)

Chemistry - DrBob222, Friday, January 11, 2013 at 9:55pm
.........BiI3 ==> Bi^3+ + 3I^-
Equil..solid.10.291E-3..3*10.291E-3

Substitute into Ksp expression and solve.
Chemistry - bhanu, Saturday, January 12, 2013 at 11:37am
6.8e-8
Chemistry - Anonymous, Sunday, January 13, 2013 at 12:56pm
6.8e-8 is oncorrect!

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