Chemistry
posted by T on .
A photon interacts with a ground state electron in a hydrogen atom and is absorbed. The electron is ejected from the atom and exhibits a de Broglie wavelength of 0.468×10−10 m. Determine the frequency (in hz) of the interacting photon.

frequency(wavelength)=speed of light.
solve for frquency. 
1.67E17

First find: E = P^2/2Me + E(first ionization)
P= h / BroglieWavelength
E(first ionization)=21.7*10^19
Me= 9.1*10^31
h= 6.626*10^34
Once E is found the find frequency:
frequency(hz)= E / h 
1.71*10^17
Right answer