Homework Help: Chemistry

Posted by T on Friday, January 11, 2013 at 2:30pm.

HELP!!!

At temperatures above 930 ∘C, PbO reduces PbS to form metallic lead (Pb). The byproduct of the reaction is SO2. Calculate the amount of lead produced (in kg) when a reactor is charged with 487.0 kg of PbS and 750 kg of PbO.

Chemistry - Steve, Friday, January 11, 2013 at 3:27pm
Looks like the reaction is

2PbO + PbS = 3Pb + SO2

487kg PbS = 487000/239.26 = 2035.44 moles
750kg PbO = 750000/223.20 = 3360.22 moles

Since each PbS needs two PbO, the PbO is the limiting reagent.

Each 2 moles of PbO produce 3 moles of Pb, so we end up with

3/2 * 3360.22mole * 207.2g/mol = 1044.36kg Pb
Chemistry - Anonymous, Friday, January 11, 2013 at 4:31pm
Its wrong
Chemistry - hina, Friday, January 11, 2013 at 9:38pm
pbo in gram/ 446.4 = ans *621.6 = final ans

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