chemistry
posted by schoolgirl on .
A photon interacts with a ground state electron in a hydrogen atom and is absorbed. The electron is ejected from the atom and exhibits a de Broglie wavelength of 3.188*10^10m Determine the frequency (in hz) of the interacting photon.

The momentum of the electron is h /(wavelength)
h is Planck's constant. Use that to compute the electron energy.
Add the electron energy to the ionization energy (13.6 eV) for the photon energy. 
4.7E15

WRONG EXPALIN PLEASE

E = P^2/2Me + E(first ionization)
P= h / BroglieWavelength
E(first ionization)=21.7*10^19
Me= 9.1*10^31
h= 6.626*10^34
frecuency(hz)= E / h 
i put the numbers into the formula but didn't worked..where's my fault? my E=5.796*10^31 ; my f=874.8039
maybe someone can tell me please what's wrong here, thx