A photon interacts with a ground state electron in a hydrogen atom and is absorbed. The electron is ejected from the atom and exhibits a de Broglie wavelength of 3.188*10^-10m Determine the frequency (in hz) of the interacting photon.
chemistry - drwls, Friday, January 11, 2013 at 11:15pm
The momentum of the electron is h /(wavelength)
h is Planck's constant. Use that to compute the electron energy.
Add the electron energy to the ionization energy (13.6 eV) for the photon energy.
chemistry - helper, Saturday, January 12, 2013 at 12:11pm
chemistry - Anonymous, Saturday, January 12, 2013 at 12:22pm
WRONG EXPALIN PLEASE
chemistry - qwerty, Saturday, January 12, 2013 at 4:14pm
E = P^2/2Me + E(first ionization)
P= h / BroglieWavelength
frecuency(hz)= E / h
chemistry - a, Sunday, January 13, 2013 at 11:11am
i put the numbers into the formula but didn't worked..where's my fault? my E=5.796*10^-31 ; my f=874.8039
maybe someone can tell me please what's wrong here, thx