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March 26, 2017

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A photon interacts with a ground state electron in a hydrogen atom and is absorbed. The electron is ejected from the atom and exhibits a de Broglie wavelength of 1.828×10−10 m. Determine the frequency (in hz) of the interacting photon.

  • Chemistry - ,

    4.329E15

  • Chemistry - ,

    wrong answer

  • Chemistry - ,

    Would you please give the formula?

  • Chemistry - ,

    chacho,could you please explain the answer when de broglie wavelength 0.468*10^-10m.

  • Chemistry - ,

    A photon interacts with a ground state electron in a hydrogen atom and is absorbed. The electron is ejected from the atom and exhibits a de Broglie wavelength of 0.468×10−10 m. Determine the frequency (in hz) of the interacting photon.

  • Chemistry - ,

    How do you use the above data and insert into the formula?

  • Chemistry - ,

    could you explain me this one
    A photon interacts with a ground state electron in a hydrogen atom and is absorbed...
    And I will explain you the formula

  • Chemistry - ,

    4.329E15 this answer is not right

  • Chemistry - ,

    7.157215*10^15

  • Chemistry - ,

    chacho's answer is right if you have in your question de Broglie wavelength of 5.908×10−10 m :-)

  • Chemistry - ,

    this answer also not righ

  • Chemistry - ,

    Formula please...

  • Chemistry - ,

    2.3E19

  • Chemistry - ,

    please give us the formula

  • Chemistry - ,

    E = P^2/2Me + E(first ionization)

    P= h / BroglieWavelength

    E(first ionization)=21.7*10^-19

    Me= 9.1*10^-31

    h= 6.626*10^-34

    frecuency(hz)= E / h

  • Chemistry - ,

    I have one question about the formula, is it E = P^2/(2Me + E)(first ionization) or E = P^2/(2Me + E(first ionization) ) ??

  • Chemistry - ,

    sorry i wrote the same formula; my questios was if the formula is:

    1- E = (P^2/2Me )+ E(first ionization)
    or
    2- E = P^2/(2Me + E)(first ionization)

    sorry for the previous post

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