Homework Help: chemistry

Posted by mike on Friday, January 11, 2013 at 12:16pm.

(a) The solubility of bismuth iodide in water is 9.091 x 10-3 M. Calculate the value of the solubility product. The dissolution products are and

chemistry - Anonymous, Friday, January 11, 2013 at 4:30pm
solubility = (x)*((x*3))^3

x=9.091*10-3

solubility = 1.84*10^-7
chemistry - Anonymous, Saturday, January 12, 2013 at 9:54am
u r the best!
chemistry - rex, Saturday, January 12, 2013 at 9:43pm
5.043*10^-7

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