Homework Help: physics

Posted by john on Friday, January 11, 2013 at 9:52am.

A 2kg and a 4kg hang freely at opposite ends of a light inextensible string which passes over a small and light pulley fixed to a rigid support calculate the acceleration of the system

physics - Elena, Friday, January 11, 2013 at 4:23pm
m₁a=m₁g -T
m₂a=m₂g-T
a(m₁-m₂)=g(m₁+m₂)
a =g(m₁+m₂)/(m₁-m₂)= ...

Answer this Question

Related Questions

physics - a 2kg and a 4kg hang freely at opposite end of a light in-extensible ...
Machanics - particles of mass 3m and 5 m hang one at each end of a light ...
math - particles of mass 3m and 5 m hang one at each end of a light inextensible...
Math - particles of mass 3m and 5 m hang one at each end of a light inextensible...
physics - A mass m1 = 6.0 kg sits on a frictionless table, and rotates at a ...
M1, Mechanics - A particle of mass 4kg is suspended from a point A on a ...
Physics - Cn u plz gv explaination 2 d solutions steps by steps briefly?Cz i ...
physics - Two packing crates of masses m1 = 10.0 kg and m2 = 4.40 kg are ...
Physics - Can you plz give explaination to the solutions steps by steps in brief...
physics - A 9.10-kg hanging object is connected by a light, inextensible cord ...

For Further Reading

First Name:
School Subject:
Answer: