Okay one last one that I've spent all night truing to figue out. 2. The width of a rectangle is 6 cm longer than its length. Its perimeter is more than 36 cm. Let l equal the length of the rectangle.
a. for the width in terms of the length.
W= l + 6= <36
b. Write an inequality for the perimeter.
c. Solve the inequality, clearly identifying the length of the rectangle.
ignore the w= l + 6= < 36!!
W=L+6
Perimeter=2(L+W)
2L+2W=P
2L+2(L+6)>36
4L>36-12
L>6
thank you!!
a. To find the width of the rectangle in terms of its length, we are given that the width is 6 cm longer than the length. So we can write the equation:
Width (W) = Length (l) + 6
b. To write an inequality for the perimeter of the rectangle, we need to know the formula for the perimeter of a rectangle. The formula for calculating the perimeter of a rectangle is:
Perimeter = 2(length + width)
We are given that the perimeter is more than 36 cm, so we can write the inequality as:
2(l + (l + 6)) > 36
Simplifying the inequality further:
2(2l + 6) > 36
4l + 12 > 36
c. To solve the inequality and find the length of the rectangle, we need to isolate the variable "l" on one side of the inequality.
Subtracting 12 from both sides of the inequality:
4l > 36 - 12
4l > 24
Dividing both sides of the inequality by 4:
l > 6
Therefore, the length of the rectangle is greater than 6 cm.