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March 1, 2015

March 1, 2015

Posted by **HELP HELP HELP MNHS** on Friday, January 11, 2013 at 6:46am.

(W/ solution please, tnx...)

- math -
**Reiny**, Friday, January 11, 2013 at 8:27am"The illumination a surface receives from a light source varies inversely with the square of the distance."

-----> I = k(1/d^2) , where I is the illumination, and d is the distance

or:

I1/I2 = d2^2/d1^2

I/(1/3)I) = 3^2 / d1^2

3 = 9/d^2

3d^2= 0

d^2 = 3

d = √3

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