math
posted by Muiz .
solve the pair of equation for x and y respectively,2xpower1  3y1 equals 4 and 4xpower1 + ypower1 equals 1

I will assume:
2x^1  3y^1 = 4 > 2/x  3/y = 4
and
4x^1 + y^1 = 1 > 4/x + 1/y = 1
double the first : 4/x  6/y = 8
keep the 2nd : 4/x + 1/y = 1
subtract them:
7/y = 7
7y = 7
y = 1
back into the 2nd:
4/x + 1/1 = 1
4/x = 2
2x = 4
x = 2