you push a 75 kg wooden box at a constant speed. the coeffiecent of kinetic friction between the box and the desk is 0.230. You pull the crate a distance of 8.75 m. How much work was done?

Explain steps please//

Multiply the friction force by the distance pulled. That will give you the work done, in Joules.

The friction force is M*g*0.23 = 169.1 Newtons

To find out how much work was done in pushing the wooden box, you need to calculate the work done against the frictional force.

The formula for work is:

Work = Force x Distance x cosine(angle)

In this case, the force you need to consider is the force required to overcome the kinetic friction between the wooden box and the desk.

The formula for the force of kinetic friction is:

Force of Kinetic Friction = Coefficient of Kinetic Friction x Normal Force

The normal force is equal to the weight of the box, which can be calculated as:

Normal Force = Mass x Gravity

where mass is given as 75 kg, and gravity is approximately 9.8 m/s^2.

Now, let's calculate the normal force:

Normal Force = 75 kg x 9.8 m/s^2 = 735 N

The force of kinetic friction can be calculated using the coefficient of kinetic friction:

Force of Kinetic Friction = 0.230 x 735 N = 169.05 N

Now, let's plug in the values into the work formula:

Work = 169.05 N x 8.75 m x cos(180 degrees)

Since the wooden box is being pushed horizontally, the angle between the applied force and the displacement is 180 degrees, resulting in a cosine value of -1.

Now, let's calculate the work:

Work = 169.05 N x 8.75 m x (-1) = -1481.69 J

Therefore, the work done in pushing the wooden box is approximately -1481.69 Joules. The negative sign indicates that the work is done against the applied force of kinetic friction, which opposes the direction of motion.