An object was fired with an initial speed of 33m/s at an angle of 32 degrees from the horizontal.
How long was it in the air?
To find how long the object was in the air, we can use the kinematic equations of motion in two dimensions. Specifically, we can use the equation for the time of flight:
π‘ = (2π£βsinπ)/π
Where:
- π‘ is the time of flight
- π£β is the initial speed of the object
- π is the launch angle
- π is the acceleration due to gravity (approximately 9.8 m/sΒ²)
Plugging in the given values:
π‘ = (2 * 33 * sin(32Β°)) / 9.8
Using a calculator, we can evaluate this expression to find the time of flight:
π‘ β 3.58 s
Therefore, the object was in the air for approximately 3.58 seconds.