Posted by Bart on .
I know the answer to this question is: 1. I got that answer by substituting 1 in for x. Please show me how I should do this the correct way.
(x/(3x+6))((x+1)/(3x6))=(1/((x^2)4))
Thank you.

Algebra 2 
Steve,
something wrong with my answer two hours ago? Here it is again.
x/(3x+6)  (x+1)/(3x6) = 1/(x^24)
factor out the 1/3 on the left side, and factor the right side
1/3 (x/(x+2)  (x+1)/(x2)) = 1/((x+2)(x2))
now put LS over a common denominator
1/3 (x(x2)  (x+1)(x+2))/((x2)(x+2)) = 1/((x+2)(x2))
multiply through by 3(x2)(x+2)
x(x2)  (x+1)(x+2) = 3
x^2  2x  x^2  3x  2 = 3
5x  2 = 3
5x = 5
x = 1 
Algebra 2 
Bart,
Steve, thank you for showing me again. Yes, I couldn't quite get it last time. I understood factoring out the 1/3 on the left side. I understood factoring the denominator on the right side. After that I have trouble. Could you please show it to me again with more steps in place?