Physics
posted by Kara on .
An electron with a horizontal speed of 4.0 * 10^6 m/s and no vertical component of velocity passes through two horizontal parallel plates. The magnitude of the electric field between the plates is 150 n/c the plates are 6.0 long
A) calculate the vertical component of the electron's final velocity. (Ans 4.0 * 10^5)
B) calculate the final velocity of the electron. (Ana4.0 * 10^6)
Please with full solution

v(x)=4•10⁶ m/s,
E=150 N/C
L= 6 (????)
t= L/v(x)
F=eE,
F=ma,
ma=eE
a=eE/m
where e = 1.6•10⁻¹⁹ C,
m=9.1•10⁻³¹ kg,
v(y)=at =...
v=sqrt{v(x) ²+v(y) ²} =…