In Rhombus PQRS PQ=3a=7 and QR = 4a-11. What is the value of a?
To find the value of a, we can use the given information about the Rhombus PQRS.
We know that the opposite sides of a rhombus are congruent. So, PQ and SR are congruent. According to the given information, PQ = 3a = 7.
To solve for a, we can set up an equation equating the two expressions for PQ:
3a = 7
Now, let's solve for a:
Divide both sides of the equation by 3:
a = 7/3
So, the value of a is 7/3.