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Posted by on Wednesday, January 9, 2013 at 10:09pm.

The pH of a solution of Sr(OH)2 is 12.42. What is its (OH^-)

  • AP Chemistry - , Wednesday, January 9, 2013 at 10:17pm

    Use pH + pOH = pKw = 14 You know pH, solve for pOH, then
    pOH = -log(OH^-).
    Substitute and solve for OH^-.

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