Math
posted by Bob on .
Before 1986, a gold bullion in the Federal Reserve Bank was rectangular and had a volume of approximately 727.7 cm3. The density of gold is 19.3 g/cm3. A pound is approximately 454 g. Find the weight of one gold bullion to the nearest tenth of a pound.

Explanation please

31

305 lbs.

30

315

hfh

30.9 lb

Mass = Density X Volume
Mass = 727.7 CM^3 X 19.3 g/cm^3
Mass = 14,044.61 g
Since a pound is approximately 454 g
Mass = 14,044.61/454
Mass/weight = 30.9 lbs