A sample of gas occupies 24.5 L at a pressure of 1.57 atm; what is the pressure if the volume is increased to 48.3 L?

0.796 atm

P1V1 = P2V2

A sample of gas occupies 29 L under a pressure of 1.3 atm. What ...

56

0.76

To solve this problem, we can use Boyle's Law, which states that the pressure of a gas is inversely proportional to its volume, when temperature and amount of gas are constant. Mathematically, this can be expressed as:

P1 × V1 = P2 × V2

Where P1 is the initial pressure, V1 is the initial volume, P2 is the final pressure, and V2 is the final volume.

Now, let's plug in the values we have:

P1 = 1.57 atm
V1 = 24.5 L
V2 = 48.3 L (the final volume we want to find)
P2 = ? (the final pressure we want to find)

Using the formula, we can rewrite it as:

1.57 atm × 24.5 L = P2 × 48.3 L

To find P2, we can rearrange the formula:

P2 = (1.57 atm × 24.5 L) / 48.3 L

Now, let's solve this equation:

P2 = (1.57 * 24.5) / 48.3
P2 = 0.913 atm (rounded to three decimal places)

Therefore, when the volume of the gas increases to 48.3 L, the pressure will be approximately 0.913 atm.