Tuesday

July 22, 2014

July 22, 2014

Posted by **Neil** on Wednesday, January 9, 2013 at 4:23pm.

1. 8a / 3b^2 / 6ab /5

2. 42x^2 + 14x / x - 7 / 2 + 6x / 21 - 3x

3. 9 + 3 / x / x / 4 + 1 /12

4. (x^-1 + x^-2)divided by (9x^-2)

Ans. #1: 20 / 9

Ans. #2: 42x^2 + 6x + 4 / -2x + 14

Ans. #3: 144 / x / 3x + 1

I don't know how to do #4

- Math For College Readiness -
**Steve**, Wednesday, January 9, 2013 at 4:35pmI have trouble interpreting you run-on compound fractions. How about some parentheses so we know what's what?

(x^-1 + x^-2)/(9-x^2)

(1/x + 1/x^2)/(9-x^2)

(x+1)/(x^2 (9-x^2))

This doesn't simplify much.

- Math For College Readiness -
**Neil**, Wednesday, January 9, 2013 at 4:42pm1. (8a / 3b^2) / (6ab / 5)

2. (42x^2 + 14x) / (x - 7) / (2 + 6x / 21 - 3x)

3. (9 + 3 / x) / (x / 4 + 1 /12)

- Math For College Readiness -
**Steve**, Wednesday, January 9, 2013 at 4:49pm1. (8a)/(3b^2) * (5)/(6ab) = (40a)/(18ab^3) = 20/(9b^3)

2. (14x)(3x+1)/(x-7) * 3(7-x) / (2(3x+1))

= 42x(3x+1)(7-x) / 2(x-7)(3x+1)

= -21x

3. (9x+3)/x / (3x+1)/12

= 3(3x+1)/x * 12/(3x+1)

= 36/x

- Math For College Readiness -
**Neil**, Wednesday, January 9, 2013 at 4:51pmThank you very much, Steve :)

**Related Questions**

Math - Derivatives - Differentiate the given function. Simplify the answer. f(x...

algebra - solve the following equation by clearing fractions show all work want ...

Math For College Readiness - Simplify: (3w - 1) / (2w^2 + w - 3) - (2 - w) / (w...

Math For College Readiness - Simplify: y - 3 / y - 2 - y + 1 / 2y - 5 + -4y + 7...

math - The rectangle given has a perimeter of 14 units. Find the value(s) of x ...

Math - If one factor of 56x^4y^3-42x^2y^6 is 14x^2y3,what is the other factor

math - which equation is equivalent to 5x-2(7x+1)=14x? why? a -9x-2=14x b -9xt1=...

Mathematics - Can someone explain to me how to solve complex fractions as if I ...

algebra - Find the complex zeros of the polynomial function. Write f in factored...

pre-calculus - find the complex zeros of the polynomial function. write F in the...