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November 26, 2014

November 26, 2014

Posted by **Deborah** on Wednesday, January 9, 2013 at 2:34pm.

-(14x)^0y^-7z.

my answer is C.

A.)-14z/y^7

B.)14z/y67

C.)z/y^7

D.)-z/y^7

Thank You.

- Math Ms.Sue -
**Steve**, Wednesday, January 9, 2013 at 2:43pm(D)

'cause

(14x)^0 = 1

- Math Ms.Sue -
**Deborah**, Wednesday, January 9, 2013 at 2:48pmSteve these - signs are throwing me off....so even though that is - (14x)to the 0 - which = 1 it is a negative still?

- Math Ms.Sue -
**Steve**, Wednesday, January 9, 2013 at 2:54pmyes. (14x)^0 = 1, so -(14x)^0 = -(1) = -1

now, (-14x)^0 = 1, because the - sign is part of what is raised to the 0 power.

Powers are done before +/- unless parens change the order.

- Math Ms.Sue -
**Deborah**, Wednesday, January 9, 2013 at 3:13pmok...that helped - I get it...thank you

- Math Ms.Sue -
**Steve**, Wednesday, January 9, 2013 at 3:18pmIt's nice when it finally clicks, eh?

Maybe it will help if you consider a leading "-" as preceded by a 0. So,

-x^2 = 0-x^2

now it is clear that the powers get done before the subtraction.

-(-2x)^-3 = 0-(-2x)^-3 = 0 - 1/(-2x)^3 = 0 - 1/-8x^3 = 1/8x^3

- Math Ms.Sue -
**Lauryn**, Tuesday, January 22, 2013 at 12:09pmSo it's d???

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