Wednesday

April 1, 2015

April 1, 2015

Posted by **anonymous** on Wednesday, January 9, 2013 at 12:05pm.

log2(x+4)-log4x=2

the 2 and 4 are lower than the g

This is what I got:

log2(x+4)+log2(4^x)=2

log2((x+4)*4^x)=2

4^x(x+4)=4

x=0 is a solution???

- math -
**justastudent**, Wednesday, January 9, 2013 at 12:51pmlog2(x+4) + log4(x) = 2

log2(x+4) + log2(x)/log2(4) = 2

log2(x+4) + log2(x)/2 = 2

2 log2(x+4) + log2(x) = 4

log2((x+4)^2) + log2(x) = 4

log2(x(x+4)^2) = 4

x (x+4)^2 = 2^4

x^3 + 8x^2 + 16x − 16 = 0

x = 0.718608

**Answer this Question**

**Related Questions**

Logarithms - I'm working on logarithmic equations and I'm stuck on how my book ...

Math - Logarithmic - Solve: 2^(5x-6) = 7 My work: log^(5x-6) = log7 5x - 6(log2...

Math - How do you solve: log2(x-1)+log2(x-2)=1 I got up to x^2-3x=0 Is it no ...

Algebra 2 - solve log2(3x-1)-log2(x-1)=log2(x+1) i have absolutely no idea how ...

add maths - Given that log2 3=h and log2 5=k, express log2 0.45 in terms of h ...

math30 - 1.Use the laws of logarithms to express log2 (6) – log2 (3) + 2log2 (...

Math - Hi! Could someone possibly help me solve this?; log2(x+4)=log2(x^2+2). ...

Math - Hi! Could someone possibly help me solve this?; log2(x+4)=log2(x^2+2). ...

math/algebra - solve the equation log2(3x-2) - log2 (x-5)=4

Pre Cal - Been trying to solve this equation and I keep getting 3...any advice ...