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August 29, 2014

August 29, 2014

Posted by **anonymous** on Wednesday, January 9, 2013 at 12:05pm.

log2(x+4)-log4x=2

the 2 and 4 are lower than the g

This is what I got:

log2(x+4)+log2(4^x)=2

log2((x+4)*4^x)=2

4^x(x+4)=4

x=0 is a solution???

- math -
**justastudent**, Wednesday, January 9, 2013 at 12:51pmlog2(x+4) + log4(x) = 2

log2(x+4) + log2(x)/log2(4) = 2

log2(x+4) + log2(x)/2 = 2

2 log2(x+4) + log2(x) = 4

log2((x+4)^2) + log2(x) = 4

log2(x(x+4)^2) = 4

x (x+4)^2 = 2^4

x^3 + 8x^2 + 16x − 16 = 0

x = 0.718608

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