Posted by **Matt** on Tuesday, January 8, 2013 at 10:58pm.

Solve sin θ = -0.204 for 90º < θ < 270º. Give your answer to the nearest tenth of a degree.

Honestly have no idea how to do this.

- trig -
**Reiny**, Tuesday, January 8, 2013 at 11:23pm
so Ø must be in quadrant II or III , but in II the sine would be positive,

so Ø is in III

get the "angle in standard position" by using +.204

sin^-1 (.204) = 11.77°

so in III, the angle is 180 + 11.77

= **191.77°**

= **191.8°** correct to one decimal

check with your calculator:

sin 191.77 = -.20398.. , ok then !

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