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4x - 5 ≤ 2(x - 7)
x^3 - 5x^2 + 2x ≥ -8
2(x^3 - 2x^2 + 3) < x(x - 1)(x + 1)

  • Math -

    1.

    4x - 5 ≤ 2x - 14
    -x ≤ -9
    x ≥ 9

    2.

    x^3 - 5x^2 + 2x + 8 ≥ 0
    (x-4)(x-2)(x+1) ≥ 0
    critical values are x = 4,2, and -1

    the graph of f(x) = (x-4)(x-2)(x+1)
    lies above the x-axis between -1 and 2, and values > 4
    so -1 ≤ x ≤ 2 OR x ≥ 4

    3.

    2x^3 - 4x^2 + 6 < x^3 - x
    x^3 - 4x^2 + x + 6 < 0
    This expression also factors,
    hint: (x+1) is a factor

    I will let you finish it, let me know what you got

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