Wednesday

April 16, 2014

April 16, 2014

Posted by **Anonymous** on Tuesday, January 8, 2013 at 10:04pm.

x^3 - 5x^2 + 2x ≥ -8

2(x^3 - 2x^2 + 3) < x(x - 1)(x + 1)

- Math -
**Reiny**, Tuesday, January 8, 2013 at 11:34pm1.

4x - 5 ≤ 2x - 14

-x ≤ -9

x ≥ 9

2.

x^3 - 5x^2 + 2x + 8 ≥ 0

(x-4)(x-2)(x+1) ≥ 0

critical values are x = 4,2, and -1

the graph of f(x) = (x-4)(x-2)(x+1)

lies above the x-axis between -1 and 2, and values > 4

so -1 ≤ x ≤ 2 OR x ≥ 4

3.

2x^3 - 4x^2 + 6 < x^3 - x

x^3 - 4x^2 + x + 6 < 0

This expression also factors,

hint: (x+1) is a factor

I will let you finish it, let me know what you got

**Related Questions**

Math - Consider the region defined by the inequalities: 0≤x 0≤y -21/...

New Age Math - Consider the region defined by the inequalities: 0≤x 0&#...

math (double checking) - I've posted this question before but I forgot to say ...

algebra 1 help - 4-2(X-5)≤4X-1 -2x+10≤4x-1 +2x +2x 4+10≤6x-1 +...

Grade 12 Calculus - Determine the absolute extrema of each function on the ...

Grade 12 Calculus - Determine the absolute extrema of each function on the ...

Grade 12 Calculus - Determine the absolute extrema of each function on the ...

Math - What is the volume of the structure bounded by the regions x^2+2y^2+z&#...

Math - Maximize P = 16x + 80y subject to these constraints: 2x + 20y ≤ 430...

Math - Minimize C=7x+3y+4z 0≤x 0≤y 0≤z 100≤2x+3y+3z 120...