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September 23, 2014

September 23, 2014

Posted by **Anonymous** on Tuesday, January 8, 2013 at 10:04pm.

x^3 - 5x^2 + 2x ≥ -8

2(x^3 - 2x^2 + 3) < x(x - 1)(x + 1)

- Math -
**Reiny**, Tuesday, January 8, 2013 at 11:34pm1.

4x - 5 ≤ 2x - 14

-x ≤ -9

x ≥ 9

2.

x^3 - 5x^2 + 2x + 8 ≥ 0

(x-4)(x-2)(x+1) ≥ 0

critical values are x = 4,2, and -1

the graph of f(x) = (x-4)(x-2)(x+1)

lies above the x-axis between -1 and 2, and values > 4

so -1 ≤ x ≤ 2 OR x ≥ 4

3.

2x^3 - 4x^2 + 6 < x^3 - x

x^3 - 4x^2 + x + 6 < 0

This expression also factors,

hint: (x+1) is a factor

I will let you finish it, let me know what you got

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