What distance would the skydiver fall during 7s of free fall ? Use the formula d= 4.9t^2, where in d is distance in meters and t is time in seconds. Pleeeeeeeeeese help me!!!!!!
240.1 right??
what is 4.9 times 49?
5 times 50 is 250, I 240 sounds close.
Thanx :)
a skydiver reaches a terminal velocity of 120 km/h. if the skydiver has a mass of 59.0 kg, what is the magnitude of the upward force on the skydrive due to wind resistance? (use g= 9.8 m/s^2)
Sure, I can help!
To find the distance the skydiver would fall during 7 seconds of free fall, we can use the formula d = 4.9t^2, where d represents distance in meters and t represents time in seconds.
Given that the time is 7 seconds, we can substitute t = 7 into the formula:
d = 4.9 * (7)^2
First, we calculate the value inside the parentheses by squaring 7:
d = 4.9 * 49
Next, we multiply 4.9 by 49 to find the distance:
d = 240.1
Therefore, the skydiver would fall approximately 240.1 meters during 7 seconds of free fall.
I hope this helps! Let me know if you have any further questions.