Homework Help: PHYSICS HELP PLEASE!

Posted by Sunny on Tuesday, January 8, 2013 at 8:04pm.

A baseball is thrown at an angle of 40.0° above
the horizontal. The horizontal component of the
baseball’s initial velocity is 12.0 meters per
second. What is the magnitude of the ball’s initial
velocity?

PHYSICS HELP PLEASE! - bobpursley, Tuesday, January 8, 2013 at 8:30pm
V(cos(theta))=12
V=12/sec40deg
PHYSICS HELP PLEASE! - bobpursley, Tuesday, January 8, 2013 at 8:30pm
oops V=12/cos40deg
PHYSICS HELP PLEASE! - Sunny, Tuesday, January 8, 2013 at 8:33pm
isn't the degree of 40 already given though? Why don't you do 12sin40?
PHYSICS HELP PLEASE! - bobpursley, Tuesday, January 8, 2013 at 8:38pm
sine would give you the vertical compnent, horizontal component is cosine times velocity

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