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March 25, 2017

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1.
y=xt1
2x+y=7

2.
x=y-2
3x-y=6

3.
y=2xt3
5x-y=-3

  • math - ,

    What do want done ?

    I can "solve" #2 :

    sub the first into the 2nd ...
    3(y-2) - y = 6
    3y - 6 - y = 6
    2y = 12
    y = 6
    then x = y-2 = 6-2 = 4

    for the 1st and 3rd, I have no clue what the
    xt1 and 2xt3 are supposed to be.
    Is the t a new variable?
    is it t^3 ?

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