Thursday

July 31, 2014

July 31, 2014

Posted by **Raelyn** on Tuesday, January 8, 2013 at 7:33pm.

I have to simplify this:

5/3sqrt(3-4)

I am not sure if you have to conjugate the denominator and multiply it with the top and bottom, then simplify from there or if the 3-4 equals -1 and you end up with i, an imaginary number in the radical. If so, I really do not understand what I would do from there. Please help!

- Algebra 2/Trig -
**majesty**, Tuesday, January 8, 2013 at 7:40pmyou have to multiply the top by the bottom then conjugate the number you get with the mean

- Algebra 2/Trig -
**Reiny**, Tuesday, January 8, 2013 at 7:40pmSo your question is really:

5/(3√-1)

If you want to make the denominator real, or to "realize" the denominator, then ....

= 5/(3√-1) * (√-1/√-1)

= 5√-1/-3

= -5√-1/3 or -5i/3

Unless there were other imaginary numbers in the rest of your questions, I suspect a typo of sorts here.

**Related Questions**

Algebra I - Hi, I would like someone to explain to me the process to get to the ...

chem - hey I am really stumped...I would really appreciate some help with this ...

english - I'm kinda getting stumped. What are some other characteristics people ...

algebra - How do I do substitution equations out of the equations in the system...

Algebra - Square roots. Woohoo. Want to check some work I did. 1. Perform ...

algebra - ur supposed to add straight down, but then i think u have to multiply ...

Physics - I'm stumped on what formula to use for the following question. A 1.5V ...

Science - I would appreciate some help if poss I am really stuck. I have an ...

Algebra - Please Simplify: (root5 a^7/2)^4 a^3/a^8 So confused, I tried figuring...

Algebra 2 - I need some help with my radical equations. I would really ...