How many atoms of carbon are in 325 g of tin (II) acetate?
First, determine how much of the 325g is carbon.
324g [(molar mass of 2 carbon)/(molar mass of Sn(CH3CO2)2)]
Then, convert grams of C to mole by dividing by C's molar mass.
Finally, convert the mole to atoms. You know for every one mole there is 6.022 × 10^23 atoms.
^I meant molar mass of 3* carbons, because there are actually 3 carbons in Sn(CH3CO2)2
^I meant molar mass of 4* carbons, because there are actually 4 carbons in Sn(CH3CO2)2
Sorry about that.
To determine the number of carbon atoms in 325 g of tin (II) acetate, we need to use the concept of moles and Avogadro's number.
Here's how to find the number of carbon atoms:
1. Determine the molar mass of tin (II) acetate (Sn(CH3COO)2).
- The molar mass of tin (Sn) is 118.71 g/mol.
- The molar mass of carbon (C) is 12.01 g/mol.
- The molar mass of acetate (CH3COO) is 59.05 g/mol.
- The molar mass of tin (II) acetate is the sum of these:
Molar mass = (118.71 g/mol) + 2 * [(12.01 g/mol) + (3 * 1.01 g/mol) + (16.00 g/mol)] = 245.77 g/mol.
2. Calculate the number of moles of tin (II) acetate in 325 g using the formula:
Moles = Mass / Molar mass.
Moles = 325 g / 245.77 g/mol = 1.3221 mol.
3. As each mole of tin (II) acetate contains two moles of carbon atoms, multiply the number of moles by 2:
Number of moles of carbon = 1.3221 mol * 2 = 2.6442 mol.
4. Finally, convert the number of moles of carbon to atoms using Avogadro's number (6.022 × 10^23 atoms per mole):
Number of carbon atoms = 2.6442 mol * (6.022 × 10^23 atoms/mol) = 1.5906 × 10^24 atoms.
Therefore, there are approximately 1.59 × 10^24 atoms of carbon in 325 g of tin (II) acetate.