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chemistry

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How many grams of oxygen are needed to burn 22.8 grams of C8H18?
80.0 g
240. g
40.0 g
20.0 g
120. g

  • chemistry - ,

    depends on the reaction. Is it

    2C8H18 + 9O2 = 16C + 18H2O ?

    If so, since you have 22.8/114 = 0.2 moles of C8H18, you will need 9/2*.2 = 0.9 moles of O2, or 28.8g

    nope. So, Fix the reaction and adjust the moles of O2 needed.

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