Posted by guest on .
How many grams of oxygen are needed to burn 22.8 grams of C8H18?
depends on the reaction. Is it
2C8H18 + 9O2 = 16C + 18H2O ?
If so, since you have 22.8/114 = 0.2 moles of C8H18, you will need 9/2*.2 = 0.9 moles of O2, or 28.8g
nope. So, Fix the reaction and adjust the moles of O2 needed.