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A rock is thrown upwards (vertically) from the ground with an initial velocity of 40 feet per second. If acceleration due to gravity is -10 feet per second squared, how high will the rock go?

  • Calc -

    You are using the wrong units, the value of -10 is associated with metres not feet. (actually in most cases it is considered -9.8 )
    I will assume you meant metres, not feet

    height = -5t^2 + 40t
    velocity = -10t + 40
    at max height, velocity = 0
    -10t+40 = 0
    t= 4

    height = -5(4^2) + 40(4) = 40 m

    If your problem stated feet, then the equation would have been
    height = -16t^2 + 40t

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