Monday

December 22, 2014

December 22, 2014

Posted by **Cadmus** on Monday, January 7, 2013 at 2:50am.

Given C+C=D, D+E=17, A+2C=D, and 2B+C=8, what is the value of A+B+C+D???

Can you also show how you got it?

- math -
**PsyDAG**, Monday, January 7, 2013 at 9:54pmTo start, if C+C=D and A+2C = D, then A = 0.

With E and B being only in one equation each, I can't figure out how to solve for B, C or D. Do you have any typos?

- math -
**Idris**, Tuesday, January 8, 2013 at 2:40amEq1 and 3. 2C=D,A=0. Eq2 and 4.C=O,B=4,D=0,E=17.Therefore A+B+C+D=21

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