Posted by phyllys on .
f(x)=x^33x^2+x12
=x^2(x3)+4(x3)
=x^2+4) (x3)
so if f(x) = 0 at x = 3,+/ 2i.
what is the f(x) factored form

PreCal. 
Damon,
(x)=x^33x^2+x12
=x^2(x3)+4(x3) Not true
That would be
x^3  3x^2 + 4x  12
=========================
You have told me that the zeros of the function are:
3
2i
2i
Therefore the factored form is:
(x3)(x2i)(x+2i)
try multiplying that out 
PreCal. 
Damon,
that is
(x^2+4)(x3)
which is
x^3  3 x^2 + 4x 12
so I think you have a typo in your opening line 
PreCal. 
phyllys,
where is the typo in which opening line? And I believe I used the wrong symbol for the factored function it's suppose to be a plus sign over a __ but I can't figure how to type this. and maybe that's what is giving us the answer you have given me. Could that be it? and that is not 12, negative 12 it's minus 12