Saturday

April 19, 2014

April 19, 2014

Posted by **phyllys** on Sunday, January 6, 2013 at 5:56pm.

=x^2(x-3)+4(x-3)

=x^2+4) (x-3)

so if f(x) = 0 at x = 3,+/- 2i.

what is the f(x) factored form

- Pre-Cal. -
**Damon**, Sunday, January 6, 2013 at 6:04pm(x)=x^3-3x^2+x-12

=x^2(x-3)+4(x-3) Not true

That would be

x^3 - 3x^2 + 4x - 12

=========================

You have told me that the zeros of the function are:

3

2i

-2i

Therefore the factored form is:

(x-3)(x-2i)(x+2i)

try multiplying that out

- Pre-Cal. -
**Damon**, Sunday, January 6, 2013 at 6:09pmthat is

(x^2+4)(x-3)

which is

x^3 - 3 x^2 + 4x -12

so I think you have a typo in your opening line

- Pre-Cal. -
**phyllys**, Monday, January 7, 2013 at 7:48pmwhere is the typo in which opening line? And I believe I used the wrong symbol for the factored function it's suppose to be a plus sign over a __ but I can't figure how to type this. and maybe that's what is giving us the answer you have given me. Could that be it? and that is not -12, negative 12 it's minus 12

**Related Questions**

Pre Cal. - The expression 81p^4 + 108 p^3 r^3 + 54p^2 r^6 + 12 pr^9 + r^12 is ...

Pre-Cal. - Which of the following results in the graph of f(x)=x^2 being ...

Pre-Cal - I'm trying to put this parabola in standard form which is: (y-k)^2=4p(...

Pre-calculus - fraction 1) 5/12+7/18-5/6 2) 3x/x-1-1/x=_____/x^2-1x 3) x+1/x^2-...

pre cal - Solve G(x) for the given domain. G(x) = 3x 2 - 2x - 1 G(6) =

pre cal - solve for x 8x-(2x-1)=3x-10

pre cal - convert the point to polar coordinates: (12,-12)

pre-cal - Find the real zeros of f (x)= 2x^3 + 3x^2 – 8x + 3

pre-cal - find an equation for the hyperbola vertices (3,0),(3,4) asymptotes:y=2...

pre cal - does anyone take pre-cal online ?