Wednesday

March 4, 2015

March 4, 2015

Posted by **Kimberly Fields** on Sunday, January 6, 2013 at 4:14pm.

- pre-algebra -
**Reiny**, Sunday, January 6, 2013 at 5:12pmnumber of 3-hour classes --- x

number of 5-hour classes --- y

x+y = 41 ----> y = 41-x

3(41)x + 5(41)y = 6437

3x + 5y = 157

sub in the 1st equation ...

3x + 5(41-x) = 157

3x + 205 - 5x = 157

-2x = -48

x = 24

then y = 41-24 = 17

they sold 24 three-hour courses and

17 five-hour courses

- pre-algebra -
**Henry**, Sunday, January 6, 2013 at 5:20pmX 3-hour classes.

(41-x) 5-hour classes.

41(3x) + 41*5(41-x) = $6,437.

123x + 8405-205x = 6,437

-82x = 6437-8405 = -1968

X = 24 3-hour classes.

41-x = 41-24 = 17 5-hour classes.

**Answer this Question**

**Related Questions**

algebra.. HELP ME!! - Mai spends 7 3/4 hours in school each day. Her lunch ...

mah - holly spend 7 and 3/5 hours in school each day. her lunch period is 1/2 ...

mah - holly spend 7 and 3/5 hours in school each day. her lunch period is 1/2 ...

Algebra 2 - I'm doing linear programming and I'm having trouble with this one ...

algebra - Parking in a student cost $3 for the first half hour and $1.50 for ...

Math - I'm doing linear programming and I'm having trouble with this one problem...

algebra - parking in a student lot cost $1 for the first half hour and $1.75 for...

Algebra - Parking in a student parking lot costs 2.00 for the first half hour ...

Algebra - Parking in a student lot cost $2 for the first half hour and $1.25 for...

math - Enrique charges $5 for every 1/5 hour he spends walking dogs. In the ...