Posted by Phil Miles on Sunday, January 6, 2013 at 3:16pm.
hanging .2 kg mass
T = string tension in Newtons
F = M a
.2(9.81) - T = .2 a
T = (1.826 - .2 a)
sliding .6 kg mass
T = .6 a
.6 a = 1.826 -.2 a
.8 a = 1.826
solve for a
now part b
again T = 1.826 - .2 a
T - 9.81*.6*0.2 = .6 a
T = .6 a + 1.177
.6 a + 1.177 = 1.826 - .2 a
.8 a = .6488
solve for a
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