Posted by **faizel** on Sunday, January 6, 2013 at 6:30am.

Given is a quadrilateral ABCD,diagonals AC and BDare such that AO=BO=CO=DO=3cm,where Ois point of intersection of AC and BD then quadrilateral ABCD is a rectangle State true or false with reason

- geometry -
**drwls**, Sunday, January 6, 2013 at 11:06am
True.

Triangle ABO is congruent to triangle CDO.(Side-angle-side equality) Triangle BCO is congruent to triangle DAO (side-angle-side equality)

Opposite pairs of sides of the quadrilateral are equal in length (due to triangle congruency).

Angles A, B, C and D are right angles.(symmetry requirement)

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