Posted by **Gian** on Sunday, January 6, 2013 at 12:59am.

A ship sails 15.0 mi on a course S40°10’W and then 21.0 mi on a course N28°20’W. Find the distance and direction of the last position from the first.

- Math -
**Steve**, Sunday, January 6, 2013 at 5:42am
convert to (x,y) values and add:

15@S40°10'W = (-9.675,-11.463)

21@N28°20'W = (-9.967,18.484)

sum = (-19.642,7.021)

or,

20.859@N70.33°W

- Math -
**Anonymous**, Monday, December 1, 2014 at 9:51pm
xdgxcg

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