Posted by Gian on Sunday, January 6, 2013 at 12:59am.
A ship sails 15.0 mi on a course S40°10’W and then 21.0 mi on a course N28°20’W. Find the distance and direction of the last position from the first.

Math  Steve, Sunday, January 6, 2013 at 5:42am
convert to (x,y) values and add:
15@S40°10'W = (9.675,11.463)
21@N28°20'W = (9.967,18.484)
sum = (19.642,7.021)
or,
20.859@N70.33°W

Math  Anonymous, Monday, December 1, 2014 at 9:51pm
xdgxcg
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