Posted by **John** on Saturday, January 5, 2013 at 11:50pm.

A ship at A is to sail to C, 56km north and 258km east of A. After sailing N25°10’E for 120mi to P, the ship is headed toward C. Find the distance of P from C and the required course to mean C.

- trigonometry -
**drwls**, Sunday, January 6, 2013 at 12:05am
duplicate question.

Call the vector from B to C "v2"

Call the vector from the starting point to C "v3".

v3 = 56 j + 258 i

Call the first leg of the voyage, from A to B, "v1"

Perform the vector operation

v2 = v3 - v1

The magnitude and direction of v2 will be your answer.

## Answer This Question

## Related Questions

- trigonometry - A ship at A is to sail to C, 56km north and 258km east of A. ...
- trigonometry - A ship at A is to sail to C, 56km north and 258km east of A. ...
- calc - At noon, ship A is 150 km west of ship B. Ship A is sailing east at 35 km...
- calc - At noon, ship A is 150 km west of ship B. Ship A is sailing east at 35 km...
- calculus - At noon, ship A is 150 km west of ship B. Ship A is sailing east at ...
- calculus - At noon, ship A is 150 km west of ship B. Ship A is sailing east at ...
- Calculus - At noon, ship A is 150 km west of ship B. Ship A is sailing east at ...
- Calculus - At noon, ship A is 180 km west of ship B. Ship A is sailing east at ...
- calculus - At noon, ship A is 110 km west of ship B. Ship A is sailing east at ...
- KSU - At 3 P.M, ship A is 150 km west of ship B. Ship A is sailing east at 35 km...

More Related Questions