Posted by **Anon** on Saturday, January 5, 2013 at 3:02pm.

for 0<=t<=21 the rate of change of the number of black flies on a coastal island at time t days is modeled by R(t)=3sqrt(t)cos(t/3) flies per day. There are 500 flies on the island at the time t=0. To the nearest whole #, what is the max # of flies for 0<=t<=21? plz solve this completely b/c the choices r: 1)500 2)510 3)520 4)530 5)540

- Differential Equation -
**drwls**, Saturday, January 5, 2013 at 3:21pm
dN/dt = 3*t^1/2*cos(t/3)

Use separation of variables.

dN = 3*t^1/2*cos(t/3)*dt

Integrate both sides.

N - N(t=0) = Integral of

3*t^1/2*cos(t/3)*dt, from t=0 to t

I don't have time to finish this. I already explained in a previous answer how to get the time of maximum fly population.

- Differential Equation -
**Anon**, Saturday, January 5, 2013 at 4:04pm
is it from 0 to 21? or 0 to 4.7??

- Differential Equation -
**drwls**, Saturday, January 5, 2013 at 11:53pm
The maximum fly population is at t = 3 pi/2 = 4.712 days. Integrate R to that limit.

The R function varies as follows: 0 at t=0, 2.835 at t=1, 3.334 at t=2, 2.807 at t=3, 1.411 at t=4 and 0 at t=4.712 The integral of R from 0 to 4.7 will be about ten. That would make the answer 510. Not much of a change.

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