Post a New Question
posted by phyllys on Saturday, January 5, 2013 at 10:33am.
find all the zeros of f(x)=x3-3x2+4x-12
you know that are all factors of 12. A little regrouping shows you have f(x) = x^3-3x^2+4x-12 = x^2(x-3) + 4(x-3) = (x^2+4)(x-3) so, f(x) = 0 at x = 3, ±2i
More Related Questions