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January 28, 2015

January 28, 2015

Posted by **Mujtaba** on Saturday, January 5, 2013 at 3:39am.

be a sample space with probability distribution P,

given by

P(s1)= 0.5, P(s2)= 0.25, P(s3)= 0.125, P(s4)= 0.125.

There are sixteen possible events that can be formed from the elements of 'S'.

Compute the probability and surprise of these events.

- Probability -
**MathMate**, Saturday, January 5, 2013 at 12:06pmI assume that each of the sixteen events has two outcomes of S, namely

P(s1,s1), P(s1,s2).....P(s4,s4).

By the multiplication rule, and assuming that the two outcomes are independent, we have

P(s1,s1)=P(s1)P(s1)=0.5*0.5;=0.25

....

P(s4,s4)=P(s4)P(s4)=0.125*0.125=0.015625

Note: The sum of probabilities of the 16 events should add up to 1.

Not sure about the surprise part.

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