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calculus

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solve the logarithmic equation. Be sure to reject any value of x that is not in the domain of the orginal logarithmic expression.

In square root x+7=1

I get this far and then get stuck, can you help me?

In square root x+7=1
e=square root x+7
e^2=x+7

x+7=e^2
x=e^2-7

  • calculus -

    looks good to me.
    something bother you about that answer?

  • calculus -

    should I go farther or is that it. I don't know it that it the final answer--I think that is what is bothering me?

  • calculus -

    the answer is exact. Going any further would just be to approximate it with a decimal. e^2-7 is just as good as π/4 or √23-ln(3).

    It's just a number.

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