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January 25, 2015

January 25, 2015

Posted by **nanuna** on Friday, January 4, 2013 at 3:09pm.

- maths -
**Steve**, Friday, January 4, 2013 at 3:37pmyou want a tangent with slope -4/3

the circle is

(x-3)^2 + (y+2)^2 = 25

2(x-3) + 2(y+2)y' = 0

y' = -(x-3)/(y+2)

when y' = -4/3, 3x = 4y+17

this occurs at (7,1) and (-1,-5)

The tangents are thus

4x+3y = 6±25

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