Posted by nanuna on Friday, January 4, 2013 at 3:09pm.
you want a tangent with slope -4/3
the circle is
(x-3)^2 + (y+2)^2 = 25
2(x-3) + 2(y+2)y' = 0
y' = -(x-3)/(y+2)
when y' = -4/3, 3x = 4y+17
this occurs at (7,1) and (-1,-5)
The tangents are thus
4x+3y = 6±25
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