Posted by **anonymous** on Friday, January 4, 2013 at 12:30pm.

what is the solution of the system of equations.

2x+2y+3z=-6

3x+5y+4z=3

2x+3y+4z=-10

- algebra -
**Steve**, Friday, January 4, 2013 at 12:32pm
(x,y,z) = (5,4,-8)

- algebra -
**anonymous**, Friday, January 4, 2013 at 12:38pm
is there away to show your work

- algebra -
**Steve**, Friday, January 4, 2013 at 4:13pm
sure. One way is to do elimination by adding and subtracting multiples of one equation from another.

subtract 2*second from 3*first:

6x+6y+9z = -18

6x+10y+8z = 6

-----------------

-4y + z = -24

subtract first from third

-y - z = 4

now add those two to get

-5y = -20

y=4

so, z=-8 and x=5

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