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April 18, 2014

April 18, 2014

Posted by **lena** on Friday, January 4, 2013 at 12:30pm.

aFe^2+(aq)+bAl(s)=cFe(s)+dAl^3+(aq)

where a,b,c and d are the lowest possible whole numbers?

a=

b=

c=

d=

- chemistry help plz -
**bobpursley**, Friday, January 4, 2013 at 12:34pmEach Fe+2 ion gets two electrons

Each Al loses three electrons. So, for each three Fe+2 ions, one must have two Al atoms.

a=3

b=2

c=3

d=2

3Fe^{+2}+2Al(s)=3Fe(s)+2Al^{+3}(aq)

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