Posted by Vanessa on Friday, January 4, 2013 at 10:50am.
a(t) = dv/dt, so
a(t) = (2pi-5) - pi cos(pi t)
as usual, max/min involve derivatives, so max a(t) occurs where da/dt = 0
da/dt = pi^2 sin(pi t)
which is zero at t = 0,1,2,3
how do we know which is min or max? 2nd derivative of a(t), which is
pi^3 cos(pi t)
so, since cos(pi t) > 0 at t=3/2,
min accel is at t=0,2 and is pi-5
max accel is at t=1,3 and is 3pi-5
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